char array in C++ -

in c++ can read file contains integers , store in char array[] ?

yes, possible store numbers file in char array:

#include <fstream> #include <iterator> #include <algorithm>  int main(int argc, char* argv[]) {     std::ifstream in("input.txt");     char arr[100];     char* end = std::copy(std::istream_iterator<int>(in),                           std::istream_iterator<int>(),                           arr);     return 0; } 

there 2 issues here. one, must know @ compile time size of array. two, each of input numbers must fit char. note formatted input, valid range not 0-255 or 0-127. it's valid character, '0', '2', 'a', 'c' , on valid inputs each character.

maybe want read file std::vector<std::string>?

#include <fstream> #include <iterator> #include <algorithm> #include <vector> #include <string>  int main(int argc, char* argv[]) {     std::ifstream in("input.txt");     std::vector<std::string> vec;     std::copy(std::istream_iterator<int>(in),               std::istream_iterator<int>(),               std::back_inserter(vec));     std::transfrom(vec.begin(), vec.end(),                    vec.begin(),                    my_transform());     return 0; } 

here read numbers std::vector<std::string>. then, manipulate each string representation of number through my_transform functor. define functor simple struct defines std::string operator()(const std::string&). function-call operator takes number , expected return manipulation of number, wish change number.