C# Sending multiple objects over same Socket -

i'm trying send multiple different objects (well, same object types, different values) 1 socket another. can send 1 object fine using following code:

client:

var buffer = new byte[1024]; var binformatter = new binaryformatter(); using (var ms = new memorystream()) {     int bytesread;     while ((bytesread = _clientreceive.receive(buffer)) > 0);     {         ms.write(buffer, 0, bytesread);     }       ms.position = 0;     message = (message)binformatter.deserialize(ms); }  

server:

var gm = new message { message = "objecttype", object = data };  using (var mem = new memorystream()) {     var binformatter = new binaryformatter();     binformatter.serialize(mem, gm);     var gmdata = mem.toarray();     client.send(gmdata, gmdata.length, socketflags.none);     client.close(); } 

but if want send multiple messages (put full client code in loop , not call client.close()) how able determine when full object has been received client? putting client code in loop this:

while (_isreceivingstarted) {     var buffer = new byte[1024];     var binformatter = new binaryformatter();     using (var ms = new memorystream())     {         int bytesread;         while ((bytesread = _clientreceive.receive(buffer)) > 0)         {             ms.write(buffer, 0, bytesread);         }         ms.position = 0;         message = (message) binformatter.deserialize(ms);     }     // stuff wait new message } 

the client hang @ _clientreceive.receive(buffer) because doesn't receive close() client , never 0 received bytes. if close connection on server, loop through , error out @ deserialize memorystream instead of blocking @ the_clientreceive.receive(buffer) in anticipation of object being sent.

i hope makes sense. pointers?

you might send header message informs receiving end how many bytes expect. similar content-length directive in http. other option, make custom termination string send @ end (obviously can't appear bit bit anywhere in serialized objects' binary payload, why former solution i'd do).