recursion - Trying to reverse a list in Scheme -

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be forewarned: homework problem. i'm trying write scheme function reverses list. '(1 2 3) becomes '(3 2 1), etc. i'm not allowed use predefined function this.

am on right track wrote here?

;myreverse (define (myreverse list)     (if (null? list) '()         (append (myreverse(cdr list)) car list)))

thanks!

well, using list name going odd, since scheme lisp-1. call lst instead.

think can foldl, cons, '(), , lst.


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