algorithm - Choosing n numbers with fixed sum -

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in code want choose n random numbers in [0,1) sum 1.

i choosing numbers independently in [0,1) , normalizing them dividing each 1 total sum:

numbers = [random() in range(n)] numbers = [n/sum(numbers) n in numbers]

my "problem" is, distribution out quite skew. choosing million numbers not single 1 gets on 1/2. effort i've calculated pdf, , it's not nice.

here weird looking pdf 5 variables:

enter image description here

do have idea nice algorithm choose numbers, result in more uniform or simple distribution?

you looking partition distance 0 1.

choose n - 1 numbers 0 1, sort them , determine distances between each of them.

this partition space 0 1, should yield occasional large result aren't getting.

even so, large values of n, can expect max value decrease well, not method.


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